How to write a results section
Statistical Significance
In this section, you present the data in a straightforward manner with no analysis of the reasons the results occurred or the biological meaning of the data (these comments are reserved for the Discussion). The results section contains a statistical analysis of the experimental data. For your seed project the appropriate statistical test necessary to compare the treatments is a Chi-Square test.
A significance test is performed to
determine if an observed value of a statistic differs
enough from a hypothesized value of a parameter
to draw the inference that the hypothesized value of the parameter is not the
true value. The hypothesized value of the parameter is called the "null hypothesis." A significance test
consists of calculating the probability of obtaining a statistic as different
or more different from the null hypothesis (given that the null hypothesis is
correct) than the statistic obtained in the sample. If this probability is
sufficiently low, then the difference between the parameter and the statistic
is said to be "statistically significant."
Just
how low is sufficiently low? The choice is somewhat arbitrary but by
convention the level
of .05 is most commonly used.
For
instance, an experimenter may have the “null hypothesis” that the humidity of a
chamber does not affect the percent germination of a seed. A group of seeds are placed into a chamber
with humid conditions and another group of seeds are placed in a chamber with
drier air conditions. After running
the experiment there are 60% of the
seeds in humid chamber germinate and
25% of the seeds germinate in the drier chamber. To determine if the difference in percent germination is
significant the experimenter has to compare the results to expected values
based on random chance. If the number
of seeds that germinated were random then we would expect 50% of the seeds to
germinate in either chamber. Therefore
the expected calculation is:
Total number of seeds tested (in one
chamber) * 0 .5
25 * .50 = 12.5 seeds
To
test whether are observed choice ratio significantly deviated from random
chance we have to calculate the chi-square values and the total chi-square
value.
(Observed
number of seeds germinated - expected
number of seeds germinated) 2
The expected number of seeds germinated
(15 – 12.5) 2 / 12.5
= 0.5 calculations
for the humid chamber
( 6.25 – 12.5) 2 / 12.5 = 3.12 calculations for the dry chamber
The
total chi-square value
3.62 The total is calculated by adding the chi
square values for both treatments
To determine
if the probability of the chi-square value is less than 0.05 you will need to
use a chi-square table (If the
probability of the chi-square value is less than .05 then you can conclude the
difference between the two treatments is not due to random chance.)
The degrees of freedom are equal to (R-1)(C-1) where R
is the number of rows and C is the number of columns. In this example, R = 2
and C = 2, so df = (2-1)(2-1) = 1. (……..in
other words the degrees of freedom for a test is the number of categories
compare minus 1).
A chi square table
can be used to determine that for df = 1, a chi square of 3.62 has a probability value less than 0.10 and greater than
0.05. Since there is a probability of
greater than 0.05 of there is no significant difference between the pattern of
isopod choice and random chance.
If the
total chi square value is greater than the critical value there is a
significant difference between the pattern of percent germination observed and
a random chance.
If the
total chi square value is less than the critical value there is not a
significant difference between the pattern of percent germination observed and
a random chance.
Critical values for the Chi Square Distribution
Significance Level
df 0.10 0.05 0.025 0.01 0.005
1 2.705 3.841 5.023 6.634 7.879
2 4.605 5.9915 7.377 9.210 10.59
3 6.251 7.8147 9.348 11.34 12.83
4 7.779 9.4877 11.14 13.27 14.86
5 9.236 11.070 12.83 15.08 16.74
6 10.64 12.591 14.44 16.81 18.54
The results of a Chi-square test should be reported in table format within your results section.
Table format
Data are organized into tables and or/figures (graphs). This lab exercise will cover the proper format for the table and a figure required to be included in the results section of your lab report.
Rules for using a Table within a scientific report:
1. Tables within scientific reports contain summary information, not the raw data collected during an experiment.
2. The table caption is located at the top of the table.
3. The table caption should define all abbreviations used in the table and the sample size of the data represented.
Example Table:
Table 1. The number of germinated seeds within each chamber section at the end of the 5 day trial. n= 25, df =1.
Treatment |
Observed % germinated seeds |
Expected % germinated seeds |
Chi-square totals |
|
15 |
12.5 |
0.5 |
Dry chamber |
6.25 |
12.5 |
3.12 |
|
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|
|
Total |
25 |
25 |
3.62 |
4. You will need to interpret the chi-square table within the text of the results section. Below is an example of the correct way to refer to the results from a chi-square test. If a table is included in a scientific report it must be referenced within the results section text.
For example:
The difference between the observed number of seeds germinated within the humid and dry chambers was not significant, p > 0.05 (Table 1).
Your results section must include one table and one figure representing
the results of your experimental data.
1. The results section must
include a table (your report will be a table with the chi-
square values). The table must have a correct table caption.
2. The results section must
include a figure and have a correct figure caption.
3. The Table and Figure must be
referred to within the text of the results section.
You can not include a
Table or Figure without referring to the Table or Figure
within the text.
4. The results section must contain more than the figure and table;
there must be a
paragraph describing the
results. Do not turn in a report with
a results section
consisting of only a table
and a figure. If you have any
questions about the
format of the results
paragraph consult the example that will be available in lab
or ask the lab instructor.
Use the class data from your Petri dish experiment
to test whether the number of colonies that were observed was greater than
would be expected by random chance.
Table 1. The raw Bio 100 class data of the number of colonies observed on
petri dishes filled with nutrient agar after a 5 day experiment, n= 6.
Sample number |
Exposed for 30 min |
Lab table surface |
Human fingertips |
Mouth or lips |
No exposure to a surface |
Table 1 |
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Table 2 |
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Table 3 |
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Table 4 |
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Table 5 |
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Table 6 |
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Totals |
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How many colonies would have been
expected for each treatment given random chance?
Expected number of colonies Total * .50 |
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Calculate the Chi- Square value for each
category:
(Observed value -
Expected value)2
=
Chi – Square value
Expected value
Chi – Square value for each category |
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Sum
all of the Chi-Square values =
___________________
How many degrees of freedom are there for this
Chi-Square test? ______________________
What is the Chi-Square critical value? ___________________________________
Are the observed number of colonies for
this experiment due to random chance? ___________________