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Look for stereoisomerism especially in these three circumstances:
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1. When there are multiple substituents on a ring.
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The easiest way to see this is to either draw in all the hydrogens or draw the ring flat and use wedges and dashes for each substituent.
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2. Whenever both carbons in a double bond contain different groups
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If either C atom in a double bond contains the same two groups there is NO stereoisomerism possible.
Divide the double bond as shown to determine cis/trans and E/Z. If both of the groups are in the same color region then they are said to be cis. If the two grous are in opposite color regions then it is trans.
I circle the higher priority group on each carbon to quickly see E from Z. |
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3. Whenever there are four different groups on a carbon atom this is called a stereogenic center.
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An odd number of stereogenic centers (*) requires that the molecule be chiral. If there is an even number of stereogenic centers you must look for internal planes of symmetry.
Any molecule that can be drawn to show an internal plane of symmetry is NOT chiral.
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Prioritizing (otherwise known as "The Cahn-Ingold-Prelog System")
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Examples:
-I is higher than -Br -D (2H) is higher than -H (1H) An aldehyde group, -(C=O)H, is higher priority than a methanol group, -CH2OH
BrCH2CH2- is higher priority than
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