Singlet and Triplet Methylene

Carbenes are reactive intermediates with a neutral divalent carbon atom and two electrons found in the two remaining orbitals. The two electrons can be the same spin (triplet) or opposite spins (singlet). Methylene, CH2, being the simplest carbene is considered the "parent" carbene--one that must be understood in order to understand any carbene. It is easy to experimentally show that triplet methylene, 3CH2, is the ground state and singlet methylene, 1CH2, is the excited state. This study will resolve two questions that chemists debated for decades before coming to a concensus: (1) Is methylene linear or bent? (2) What is the energy difference between the singlet and triplet states (DEST). In this lab we will make use of variational calculations to probe the effect of electron correlation and basis set on the answers to these two questions.

Is CH2 linear or bent?

Wavefunctions for CH2

Assuming that the two non-bonded valence electrons will go into the two unused valence orbitals on carbon we can write unnormalized wavefunctions for the triplet and singlet states of methylene. The triplet state has both electrons of the same spin. The Pauli Exclusion Principle allows only one way to place two electrons of the same spin (by convention they are both alpha spin) in two orbitals. There are three ways to obtain a singlet state: both the alpha and beta electrons in the red orbital, both electrons in the blue orbital, or a linear combination of one electron in each orbital. The relative importance of each "determinant" (electron configuration) to the overall wavefunction is dictated by the coefficients c1, c2, and c3. Hartree-Fock theory describes wavefunctions using only one determinant. For most molecules, there is only one important determinant but for singlet carbenes that is not the case. Complete active space self-consistent field (CASSCF) theory allows the user to determine how many electrons and orbitals are important to the question at hand. The wavefunctions shown below are those described by a CAS(2,2) calculation, where all ways of puting two electrons in two orbitals are considered. A more complete wavefunction would consider all of the valence electrons in all of the valence orbitals. For CH2 that would be a CAS(6,6).

Since RHF and CASSCF are variational, the lowest energy is closest to the true Schrödinger solution. Increasing the number of basis functions will give a better description of this molecule. We'll start with a very small basis set, 3-21G, and progress to a very large basis set, 6-311++G(3df,3pd). We will find out whether the computational description of methylene approaches the accepted values as the basis set and electron correlation are increased.

Procedures:

(Computation set 1: four calculations) Optimize the linear and bent geometries of methylene

(Computation set 2: three calculations) Effect of electron correlation on bond angles and DEST

(Computation set 3: six calculations) Effect of basis set on bond angles and DEST

Analysis

Consider the following questions: