

Acetamide, CH3CONH2, like all amides, has a significantly higher C-N bond rotation barrier than a normal sigma bond. This hindered rotation of the C-N bond can lead to differences in the NMR signals of the atoms atached to nitrogen. The two protons attached to N in acetamide (blue and green) are inequivalent at low temperatures but become averaged by C-N rotation at higher temperatures. Typical bond rotation barriers for amides in solution are experimentally determined by NMR to be between 17 and 22 kcal/mol. However, the acetamide enolate, [CH2CONH2]-, has a much lower barrier. According to recent NMR experiments, the enolate has free rotation at all accessible temperatures. Based on this knowledge, the maximum barrier possible for acetamide enolate is 10 kcal/mol and is probably considerably less than that.
The study of amide C-N rotation barriers is not just an esoteric exercise--amide C-N bonds make up protein backbones. The prefered amide conformations play an important role in enzyme structure and the barrier to rotation has an effect on the rigidity of that structure. The rigidity of an enzyme's structure can affect its selectivity in binding substrates.
In this experiment we seek to use quantum chemical methods to understand the nature of the hindered C-N bond rotation in acetamide and contrast it with the barrier of its enolate.
AM1 Geometries: Do all exploratory work to find the global minimum energy geometry and the lowest energy transition state before using higher levels of theory. Only the best geometries (i.e., the global minimum and the lowest energy transition state) will be re-optimized at the higher level of theory.
AM1 Minima
First, use the AM1 method to find the global minimum geometry of acetamide and its enolate.
AM1 Transition States
- Consider all of the possible conformations that could be present.
- Verify that your structure is a true minimum by making sure that all of the frequencies are real ("positive").
- Verify that it is a global minimum by comparing energies with your neighbors to find the lowest energy conformation (or calculate all possibilities yourself to be sure).
The transition states will also be computed, first, at AM1 level of theory. The transition state for C-N bond rotation is Cs symmetry. Evaluate the structure of your two minima and find the Cs symmetric transition structure that would average the two protons on N. Since any rotation about C-N breaks the symmetry plane the optimized geometry should correspond to the proper TS for C-N rotation. As long as the Cs symmetry is imposed on your starting geometry, Gaussian will not break that symmetry plane.
- Prepare the geometry:
- Start from your AM1-optimized global minimum geometry;
- rotate the C-N bond using a dihedral angle (OCNH);
- Symmetrize the molecule.
- Submit the job:
- If the Cs symmetry is recognized you can submit the calculation as an optimization.
- If you're having trouble getting Gaussian to recognize your symmetry then you can take the more general method for finding a TS:
- Change the job type to "Transition Search"
- Type "opt=noeigentest" in the extra keyword section
- Submit the job.
- This can easily go astray. If it doesn't work then we need to pull out the big guns: Edit as before but change to "opt=(ts,noeigentest,calcall)". This calculation may take a very long time.
- Verify that the transition state is correct:
- inspect it and see if the geometry makes sense
- compare your energy with your neighbor--the lowest energy TS is the one you want
- calculate a frequency from the optimized geometry
- make sure that ONE and only one of your frequencies is imaginary ("negative").
Semi-emipirical calculations are not adequate to fully characterize these processes and, therefore, we will re-optimize the important geometries at a higher level of theory. Semi-empirical calculations partially (or wholly) neglect overlap of non-adjacent atomic orbitals (e.g., the N and O orbitals in acetamide). This overlap is important in this system. Using Hartree-Fock theory will give better answers. Since we want to investigate anions, we will need to use diffuse functions ("+") to get the best answers, HF/6-31+G(d). Since the optimal geometry using this method will differ significantly from that obtained using AM1, we will re-optimize the important molecules using this higher level of theory. The AM1 calculations were good enough to give us the global minimum and the lowest enegy transition state for each molecule but we'll only use these semi-empirical calculations as a stepping stone for the final calculations (below). Starting at the AM1-optimized geometries saves time because it is closer to the HF geometry than any guess we could make and therefore will take fewer optimization steps to find the new geometry.
Complete these 3 data tables with your HF/6-31+G(d)-optimized parameters. Also include pictures for all final geometries. Note that:
Consider the following issues:
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